-6a^2+24a+126=0

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Solution for -6a^2+24a+126=0 equation:



-6a^2+24a+126=0
a = -6; b = 24; c = +126;
Δ = b2-4ac
Δ = 242-4·(-6)·126
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-60}{2*-6}=\frac{-84}{-12} =+7 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+60}{2*-6}=\frac{36}{-12} =-3 $

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